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电磁场原理题与答案 1010101.1 根据算符∇ 的微分性与矢量性,推导下列公式： ∇(A⋅ B) = B× (∇ × A) + (B ⋅ ∇)A + A× (∇ × B) + (A⋅ ∇)B A A A (A )A 2 × (∇ × ) = 1 ∇ 2 - ⋅ ∇ 【解】记∇(A⋅ B) = ∇